Math, asked by sudharanigupta7, 1 year ago

1250= 2^n-7×2^n-4
Find n.
Please solve it
Very urgenttttt........

Answers

Answered by prateekbana9613
1

2^{n-7}*2^{n-4}=1250\\2^{n-4-3}*2^{n-4}=1250\\2^{n-4}*(2^{-3}*1)=1250\\2^{n-4}=10000\\log_{2}2^{n-4}=log_{2}10000\\n-4=13.28

Answered by 0717
1

Hey

Here is the answer...

Given :- 2^n-7×2^n-4 = 1250

Here :- 1250 = 2×5×5×5×5=2×5^4

Now :- 2^n-7×2^n-4×2^3 = 2×5^4×2^3 (multiplying 2^3 on both sides)=>2^n-7+3×5^n-4 = 2^4× 5^4 => 2^n-4×5^n-4 = 2^4× 5^4 => 10^n-4 = 10^4 ( based are same powers will be equal)

=>n-4=4

=>n=4+4

=>n=8

Hope it will help u....

Thnqs..




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