Question

125a^3+b^3+64c^3-60abc​

Answer 1

A^3 + b^3 +c^3 -3abc = (a+b+c)(a sq + b sq + c sq -ab-bc-ca)

Here a=5a

b=b

c=4c

On substitution:

=(5a+b+4c)(25a^2 + b ^2 + 16c^2 -5ab-4bc-20ac)