127 ml of a gas at 136°C and 758 mm pressure
weigh 0.4524 g. If 1 mL of hydrogen at S.T.P.
weighs 0.00009 g, calculate the vapour density and
molecular mass of the gas. [Ans. 59.45, 118.90
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Explanation:
volume=380 ml=0.380 liters
temperature= 270c=273+27=300K
Now, using by formula
PV=nRT (R= gas constant= 8.2×102
n=RTpv=8.2×102×3001.052×0.380=0.0162
Now, given mass of the gass is 0.455
no of moles= molarmassmass
molar mass=noofmolesmass
0.01620.455=28.08g/mole
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