Question

127 Three times the trust of the there consecutive add integers is 3 more than twice the third Poteger. Find the third Integer. HOGA​

Answer 1

Answer:

${\red{ANSWER}}$

Let the three consecutive odd integers be x, x+2, x+4

Three times the first of three consecutive odd integers is 3 more than twice the third.

∴ 3x=2(x+4)+3

$\pink{∴ x=11}$

Hence, the third integer is 11+4=15.

Hence, This is Answer

Answer 2

Step-by-step explanation:

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