Question

129/2squere×5 power 7×7power5
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Answer 1

To have an terminating decimal expansion the denominator must have only 2 and 5 as its factors in the simlified form of fraction for any degree or power of 2 and 5

denominator = 2^2 × 5^7 × 7^5

Since it have 7 also in its prime factors. Thus it doesn't have an terminating decimal expansion.