Question

12a^2-20a+16
Factorise

Answer 1

$Given \: Quadratic \: polynomial : \\12a^{2} - 20a + 16$

$12a^{2} - 20a + 16 \\= 4\times 3a^{2} - 4 \times 5a + 4 \times 4$

/* Common number is 4 */

$= 4( 3a^{2} - 5a + 4 )$

Therefore.,

$\red { Factors \:of \: polynomial }\green { = 4( 3a^{2} - 5a + 4 ) }$

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