Question

12g of potassium sulphate dissolves in 75g of water at 60°C. What is its solubility in water at that temperature?

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Answer 1

Given Data:

75g of water dissolves = 12g of potassium sulphate

So, 100g of water will dissolve =

$\frac{12}{75} \times 100$

= 16g

Answer 2

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75g of water dissolves = 12g of potassium sulphate

So, 100g of water will dissolve =

12/75 × 100

= 16g

.

Hope it helps