Math, asked by ltha52303, 1 month ago

12p^3 + 3pq + 6p^2 + 4pq​

Answers

Answered by aastha2538
0

Answer:

... (p^3+4p^2q+4pq^2/3p^2q-5pq^2-2q^3)*(27p^3+q^ 3)/(p+2q)^3:(9p^2-3pq+q^2)/p^ ... p 3+4 p 2 q +4 p q 2 3 p 2 q −5 p q 2−2 q 3)·27 p 3+ q 3( p +2 q )3: f ... (4p3q3+3p3+12p2q-15pq2-6q3) (3p+q)•(9p2-3pq+q2) ...

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