Question

12P. A bullet of mass (.0; ky moving with a speed of 90m/s enters a heavy wooden block and is stopped after a distance of 60cm. What is the average resistive force exerted by the block on the bullet?​

Answer 1

Answer:

12 p bullets exerts TR1295 pressure in simple words it would be around 411 Newton pressure

Answer 2

Explanation:

Given,

m=0.04kg

u=90m/s

v=0m/s

S=60cm

From 3rd equation of motion,

2aS=v^2 −u^2

a=−u^2/2s

a=− 90×90/2×60×10^−2

=−6750m/s^2

The resistive force, f=ma

f=−0.04×67.5a

f=−270N