Question

12th
Integration
$\frac{ log(x) }{x} dx$
​

Answer 1

Answer:

Step-by-step explanation:

We have,

$\sf{\displaystyle\int\dfrac{log(x)}{x}\,dx}$

$\bf{Put\,\,\,log(x)=t}$

$\bf{\implies\,\dfrac{dx}{x}=dt}$

So,

$\sf{\displaystyle=\int\,t\,dt}$

$\sf{\displaystyle=\dfrac{t^2}{2}+C}$

$\sf{\displaystyle=\dfrac{\left\{log(x)\right\}^2}{2}+C}$