12th term of an A.P is - 13 and sum of first four terms is 24 find the sum of first 20 terms
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Answer:
a12=-13
s4=24
s20=?
-13=a+11d
- -13-11d=a
24=4/2(2(-13-11d)+3d)
24/2=-26-22d+3d
12=-26-19d
12+26=-19d
38=-19d
d=-2
-13-11d=a
-13-11(-2)=a
-13+22=a
9=a
s20=20/2(2×9+19×-2)
s20=10(18-38)
s20=-200
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