Math, asked by radhika4471, 10 months ago

12x*2 - 19x - 21
find the zeros of the polynomial

Answers

Answered by Suresh2003
0

Answer:

Zeroes of the polynomial

7/3 and - 3/4

Step-by-step explanation:

12x²-19x-21=0

12x²+9x-28x-21=0

3x(4x+3)-7(4x+3)=0

(3x-7)(4x+3)=0

3x-7=0

X=7/3

4x+3=0

X=-3/4

Answered by ramanaasn
0

Answer:

the zeros of the polynomial is -4/3 and 7/3

Step-by-step explanation:

12x*2-19x-21

=12x*2-28x+9x-21

=4x(3x-7)+3(3x-7)

=(4x+3)(3x-7)

4x+3=0 3x-7=0

4x=-3 3x=7

x=-4/3 x=7/3

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