what is the remainder when the number 101102103104105106107..1481149150 is divided by 9?
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Answer:
2
Step-by-step explanation:
do the sum the digits
we will get 65 ones
total 50 digits so 50 ones + from 110 ----119 , 101 we will get 12
+121,131 ,141
so 50+12+3 = 65 ones
No: of twos are 6
no of threes are 6
no of fours are 6
no of fives are 6
no of sixes , sevens , eights , nines are 5 each
so total
1* 65 + 2 * 6 + 3*6 + 4 * 6 + 5*6 + 5 [ 6+7+8+9] = 299
so if the sum of the numbers is divisible by 9 the number is also divisible by 9 if you divide 299 / 9 reminder is 2
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