Question

what is the remainder when the number 101102103104105106107..1481149150 is divided by 9?

Answer 1

Answer:

2

Step-by-step explanation:

do the sum the digits

we will get 65 ones  

                          total 50 digits so 50 ones + from 110 ----119 , 101 we will get 12        

                                                                              +121,131 ,141

so 50+12+3 = 65 ones

No: of twos are 6

no of threes are 6

no  of fours are 6

no of fives are 6

no of sixes , sevens , eights , nines are 5 each

so total

    1* 65 + 2 * 6 + 3*6 + 4 * 6 + 5*6 + 5 [ 6+7+8+9] = 299

so if the sum of the numbers is divisible by 9 the number is also divisible by 9 if you divide 299 / 9 reminder is 2