Question

Calculate the compound interest for the second
year on 12,000 invested for 3 years at 10%
per year. Also, find the sum due at the end of
the third year.​

Answer 1

Answer:

Sum is equal to ₹11000.

Answer 2

${\huge{\huge{\underline{\underline{\mathrm{\red{QuesTion:-}}}}}}}$

Calculate the compound interest for the second

year on * 12,000 invested for 3 years at 10%

per year. Also, find the sum due at the end of

the third year.

${\huge{\huge{\underline{\underline{\mathrm{\green{SoluTion:-}}}}}}}$

$\underline {\purple{\boxed{ \sf{Given:-}}}}$

✍︎Principal=12000

✍︎Rate=10%

✍︎Time=3 years

Lets understand

☞︎︎︎The money given to the borrower is called Principal.

☞︎︎︎the extra money given to the lender by borrower is called interest.

☞︎︎︎the money given to borrower for a specified time is called Time.

lets learn the formula for calculacting amount for CI(compound interest).

$\mathrm{ a = p(1 + \frac{r}{100}) {}^{n} }$

 ‎

$\underline {\green{\boxed{ \sf{Here:-}}}}$

 ‎

 ‎

A=Amount

P=Principal

r=rate

n=time

 ‎

 ‎

lets solve the formula

$\mathrm{ a = 12000( 1 + \frac{10}{100}) {}^{3} }$

 ‎

 ‎

100 will be simplified by 10

so

 ‎

 ‎

$\mathrm{ a = 12000( 1 + \frac{1}{10}) {}^{3} }$

 ‎

 ‎

now lets evaluate the formula

 ‎

 ‎

$\mathrm{ a = 12000( \frac{11}{10}) {}^{3} }$

 ‎

 ‎

$\mathrm{ a = 12000 \times \frac{11}{10} \times \frac{11}{10} \times \frac{11}{10} }$

 ‎

 ‎

all zeroes of 10s will be divided by 12,000

 ‎

 ‎

$\mathrm{ a = 12 \times \frac{11}{1} \times \frac{11}{1} \times \frac{11}{1} }$

 ‎

 ‎

there is no value of 1 in the formula so

we can write formula as

 ‎

 ‎

$\mathrm{ a = 12 \times \frac{11}{} \times \frac{11}{} \times \frac{11}{} }$

 ‎

 ‎

now lets evavulate

 ‎

 ‎

$\mathrm{ a = 12 \times \frac{11}{} \times \frac{11}{} \times \frac{11}{}=15972 }$

 ‎

 ‎

$\underline {\purple{\boxed{ \sf{Amount=15972}}}}$

 ‎

 ‎

lets find out CI(compound interest)

CI=A-P

 ‎

 ‎

CI=15972-12000

=3972

 ‎

 ‎

The amount is 15972 so the sum due at the end of third year will be 15,972.

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