12x^2-35x+25 pls factorise this equation by splitting the middle term
Answers
Answer:
12x2+35x+25
Final result :
(4x + 5) • (3x + 5)
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((22•3x2) + 35x) + 25
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 12x2+35x+25
The first term is, 12x2 its coefficient is 12 .
The middle term is, +35x its coefficient is 35 .
The last term, "the constant", is +25
Step-1 : Multiply the coefficient of the first term by the constant 12 • 25 = 300
Step-2 : Find two factors of 300 whose sum equals the coefficient of the middle term, which is 35 .
-300 + -1 = -301
-150 + -2 = -152
-100 + -3 = -103
-75 + -4 = -79
-60 + -5 = -65
-50 + -6 = -56
-30 + -10 = -40
-25 + -12 = -37
-20 + -15 = -35
-15 + -20 = -35
-12 + -25 = -37
-10 + -30 = -40
-6 + -50 = -56
-5 + -60 = -65
-4 + -75 = -79
-3 + -100 = -103
-2 + -150 = -152
-1 + -300 = -301
1 + 300 = 301
2 + 150 = 152
3 + 100 = 103
4 + 75 = 79
5 + 60 = 65
6 + 50 = 56
10 + 30 = 40
12 + 25 = 37
15 + 20 = 35 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 15 and 20
12x2 + 15x + 20x + 25
Step-4 : Add up the first 2 terms, pulling out like factors :
3x • (4x+5)
Add up the last 2 terms, pulling out common factors :
5 • (4x+5)
Step-5 : Add up the four terms of step 4 :
(3x+5) • (4x+5)
Which is the desired factorization
Final result :
(4x + 5) • (3x + 5)
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Here is your answer
Factorising by splitting the middle terms as