Question

If had of 210 and 55 is expressible in the form 210x5-55x find value of x

Answer 1

Answer:

Step-by-step explanation:

5(210 - 11x) = 210

210 - 11 x = 42

11 x = - (42 - 210)

11 x = 168

x = 168/11

5(210 - 11 x) = 55

210 - 11 x = 11

11 x = - (11 - 210)

x = 199/11

Answer 2

Answer:

x = -19

Step-by-step explanation:

Let us find the first (HCF) of 210 and 55.  

By Applying Euclid division lemna on 210 and 55,

We get this,

210 = 55 × 3 + 45  

55 = 45 × 1 + 10  

45 = 4 × 10 + 5  

10 = 5 × 2 + 0  

We had observed that the remainder at this step is zero.

So, the last divisor.

i.e., 5 is the HCF of 210 and 55.  

∴ 5 = 210 × 5 + 55x

⇒ 55y = 5 - 1050 = -1045

x = -19