12x²+61x+77, Find the factors of the given polynomial
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Answered by
68
12x^2 + 61x + 77
= 12x^2 + 28x + 33x + 77
= 4x ( 3x + 7) + 11(3x +7)
= (3x + 7)( 4x + 11)
= 12x^2 + 28x + 33x + 77
= 4x ( 3x + 7) + 11(3x +7)
= (3x + 7)( 4x + 11)
Answered by
118
Given Quadratic expression
12x² + 61x + 77
Splitting the middle term ,
= 12x² + 28x + 33x + 77
= 4x( 3x + 7 ) + 11( 3x + 7 )
= ( 3x + 7 )( 4x + 11 )
Therefore ,
12x² + 61x + 77 = ( 3x+7 )( 4x+11 )
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