3y²-2y-1, Find the factors of the given polynomial
Answers
Answered by
11
3y^2 - 2y - 1
= 3y^2 - 3y + y - 1
= 3y(y-1)+ 1(y-1)
= (3y + 1)(y-1)
= 3y^2 - 3y + y - 1
= 3y(y-1)+ 1(y-1)
= (3y + 1)(y-1)
Answered by
39
Given polynomial 3y²-2y-1
Splitting the middle term ,
= 3y² - 3y + 1y - 1
= 3y ( y - 1 ) + 1( y - 1 )
= ( y - 1 )( 3y + 1 )
••••
Splitting the middle term ,
= 3y² - 3y + 1y - 1
= 3y ( y - 1 ) + 1( y - 1 )
= ( y - 1 )( 3y + 1 )
••••
Similar questions