Math, asked by VaishnaviAsok, 10 months ago

(12y^2 + 17y - 4) + (9y^2 - 13y + 13)

Answers

Answered by ayushhhhhhh
1

Answer:

21y2 + 4y + 9

Step-by-step explanation:

((12•(y2))+17y)-4)+((9y2-13y)+13)

((22•3y2) + 17y) - 4) + (9y2 - 13y + 13))/

The first term is, 21y2 its coefficient is 21 .

The middle term is, +4y its coefficient is 4 .

The last term, "the constant", is +9

Multiply the coefficient of the first term by the constant 21 • 9 = 189

: Find two factors of 189 whose sum equals the coefficient of the middle term, which is 4 .

the answer is 21y2 + 4y +9

Answered by smaheswari1254
0

= ( 12+9) y^2 +(17-13)y + (13-4)

= (21) y^2 + ( 4y) +9

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