Math, asked by abhishekbarure, 6 months ago

13
1) If sec thita =13/12
find tan thita​

Answers

Answered by MathsLover00
2

 \pink{given : } \\  \\  \sec( \alpha )  =  \frac{13}{12}  =  \frac{hypotenuse}{adjustent}  \\  \\   \blue{to \:  \:  \: find \:  \:  : } \tan( \alpha )  \\  \\   \red{solution : } \\  \\ opposite =  \sqrt{ {hypt}^{2}   -  {adjut}^{2} }  \\  \\ oppo =  \sqrt{ {13}^{2}  -  {12}^{2} }  \\  \\ oppo \:  =  \sqrt{169 - 144}  \\  \\ oppo =  \sqrt{25}  \\  \\ oppo = 5 \\  \\  \pink{hence} \\  \\  \tan(  \alpha )  =  \frac{oppo}{adjust}  \\  \\  \tan( \alpha )  =  \frac{5}{12}

HOPE IT HELPS TO U

Answered by vikaskumar2000
0

Answer:

tan thita = 5/12

Step-by-step explanation:

sec thita = K/A = 13/12

K= 13. A= 12

We know that

K^2 = A^2 + L^2

L^2 = K^2 - A^2

L^2 = (13)^2 - (12)^2

L^2 = 169 - 144

L^2 = 25

L = 5

then , we know that

tan thita = L/A

tan thita = 5/12

Similar questions