Question

13
14) D
14. A particle moves in a straight line with a constant
acceleration. It changes its velocity from 10 ms-1
to 20 ms-1 while passing through a distance
135 m in t second. The value of t is
[AIPMT (Prelims)-2008]
(1) 9
(2) 10
(3) 1.8
(4) 12
15 The distance travelled by a particle starting from rest
19.

Answer 1

Explanation:

V=u+at

20=10+a*t

at=10

Now,

S=ut+(1/2)at^2

135=10t+(1/2)10t

135=30t/2

t=270/30

t=9secs