13/2 and -3 are zeros of the polynomial 2x^2-7x-39
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Answer:
Yes. The given statement is true.
Step-by-step explanation:
2x² - 7x - 39
= 2x² + 6x - 13x - 39
= 2x (x + 3) - 13 (x - 3)
Taking (x + 3) as common,
(x + 3) (2x - 13)
The given equation has two solutions that are -3 and 6.5
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