Question

(13^3 + 7^3)/(169+49-x) = 20
find x​

Answer 1

Step-by-step explanation:

(13³ + 7³)/(169+49-x) = 20

(2197 + 343)/(218-x) = 20

2540/218-x = 20

127/218-x = 1

127 = 218 - x

x = 218-127

x = 91

Answer 2

The value of x is 91

Explanation:

We have given an equation : $\dfrac{13^3 + 7^3}{169+49-x}=20$

Since , $13^3=13\times13\times13=2197$

$7^3=7\times7\times7=343$

Put theses values in the above equation , we will get

$\dfrac{2197 + 343}{169+49-x}=20$

Simplify

$\dfrac{2540}{218-x}=20$

$\Rightarrow\ 2540=20(218-x)$

$\Rightarrow\ \dfrac{2540}{20}=218-x$

$\Rightarrow\ 127=218-x$

$\Rightarrow\ x=218-127$

$\Rightarrow\ x=91$

Hence , the value of x is 91.

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