13. 5 years ago a man was 7 times as old
as his son. After 5 years he will be
thrice as old as his son. Find their
present
ages.
Answers
Answer:
Answer
Let Five years ago the age of son be x years and age of father be 7x years
Present age of son =x+5
Present age of father =7x+5
5 years later their age will (x+10) and (7x+10)
∴7x+10=3(x+10)
7x−3x=20
4x=20
x=5
So, the present age of son=x+5=5+5=10years
and the present age of father=7x+5=35+5=40years
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Answer:
Their present age of the man & his son is 40 years and 10 years respectively.
Explanation:
Question says that,
5 years ago a man was 7 times his son's age. 5 years hence the man becomes 3 times his son's age.
Find their present age.
If we assume the age of the son 5 years ago was years.
Then, the man's age 5 year ago was 7 times
Or, years.
Therefore, present age of
The man will be years.
His son will be years.
Now, 5 years later
The man's age years.
Son's age years.
Given,
The man's age = 3× the age of his son.
Or, we can say that
Solving for
Hence, their present age of
➪ The man is
➪ His son is