13.8g of n2o4 was placed in a little reaction vessel. at 400k allowed to attain equilibrium
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Well at equilibrium the total pressure was found 9.15bar.Kc kp and partial pressure need to be calculated..
The formula is pv=nrT and the total volume is 1l.The molecular mass is n2o4 which is 92g and the moles are 13.8gm/92g that is 0.15 Constant of gas=0.083 mole=1k-1 and temperature T =400kp
since pv=nrt p*1l=0.15*0.083 that is 4.98 bar.
rahman92:
direct kor kai dikha do
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