Question

13. A 26 m ladder is placed against the wall in such
a way that the foot of the ladder is 10 cm away
from the wall. How up on the wall is the upper
end of the ladder ?​

Answer 1

Answer:

I think the distance between wall and inclined ladder is 10m. not 10 cm.

and I have drawn fig. according to it.

from fig.

it is a right angled triangle

wall length from the ground to the inclined ladder spot

using Pythagoras thoerem

\begin{lgathered}{26}^{2} = {10}^{2} + {x}^{2} \\ {x }^{2} = 676 - 100 \\ {x}^{2} = 576 \\ x = 24\end{lgathered}262=102+x2x2=676−100x2=576x=24

hope it helps..