Question

13. A and B together can do a work in 25 days.
They work to together for 15 days and then B
leaves. A finishes the rest of the work in 20
days. How many days would each take to
complete the work seperately?​

Answer 1

Answer:

A and B can do (1/25)th part of the work in a day.

In 15 days that A and B worked together they completed (15/25) or (3/5)th of the work and what remained was (2/5)th of the work.

A completed the (2/5)th part of the work in 20 days. So A would have taken 20/(2/5) = 50 days to complete the work, working alone.

B alone does (1/25)-(1/50) = (1/50)th of the work in a day.

So A and B would both take 50 days to the same work, working alone.

Check: In 15 days A and B did 15[(1/50+(1/50)] = 15*2/50 = 3/5th of the work. and the remaining (2/5) took A (2/5)*50 = 20 days. Correct. Hope it helps.Mark me as brainlinist.