Question

13. A cricket ball of mass 100 gm
moving with a speed of 40 ms-1 is
brought to rest by a player in 0.02s.
Find the average force applied by the
player,​

Answer 1

Answer:

F= 200 N

Explanation:

a= v-u/t

=0-40/0.02

a= 2000m/s^2

now F= ma

= 100/1000*2000

F=200N

Answer 2

Force=Mass(kg)*Acceleration(m/s²).

Mass=100g=0.100kg.

Acceleration=velocity/time=-40/0.02=2000m/s².

Force(N)=0.100g*2000m/s².

Force=200N.