Two nuclides A and B are isoneutronic. Their mass are 76 and 77 respectively. If atomic no. of A is 32 then atomic no. of B will ne
Answers
Answer:
33 is ans for that one
74-30 =33
Given,
Two nuclides A and B are isoneutronic.
The atomic mass of A = 76
The atomic mass of B = 77
The atomic number of A = 32
To find,
The atomic number of B.
Solution,
We can easily find the atomic number of B by following the given steps.
Now,
We know that the atomic mass of an element is the sum of neutrons and protons.
So,
The atomic mass of A = 76
Number of neutrons (N) + number of protons (P) = 76
N + P = 76 --- (1)
We know that the atomic number of an element is equal to the number of electrons or protons.
The atomic number of A = 32
So,
Number of protons in A = 32 --- (2)
From equation 1,
N + P = 76
N + 32 = 76 (Putting the value of protons from equation 2)
N = 76-32
N = 44
A and B are isoneutronic. So, the number of neutrons in both the elements will be the same.
Number of neutrons in B = 44
The atomic mass of B = 77
Number of protons + number of neutrons = 77
Protons + 44 = 77
Protons = 77-44
Number of protons in B = 33
The atomic number of B will be equal to the number of protons.
Hence, the atomic number of B will be 33.