Question

13. A cylindrical water tank has base area equal to
616 sqm. If it's height is 48 m, find the lateral
surface area of the tank.

​

Answer 1

Answer...

$\sf \: base \: area \: = {616m}^{2} \\ \sf \pink{area \: of \: circle \: = \pi {r}^{2} } \\ \sf \: \frac{22}{7} {r}^{2} = 616 \\ \sf = {r}^{2} = \frac{616 \times 7}{22} \\ \sf = {r}^{2} = 196 \\ \sf = r = \sqrt{196} \\ \sf = r = 14 \\ \\ \sf\pink {lateral \: surface \: area \: = 2\pi rh} \\ \sf = 2 \times \frac{22}{7} \times 14 \times 48 \\ \sf = \frac{2 \times 22 \times 14 \times 48}{7} \\ = \sf\frac{29568}{7} \\ = \sf\frac{ \cancel{29568}}{ \cancel{7}} = {4224m}^{2}$