Question

13. A die is thrown once. Find the probability of getting (i) a prime number (ii) a number lying b/w 2 and 6 (iii) an odd number.
(a)1/2, 1/2 and 1/2
(b)1/3, 1/2 and 1/6
(c)2/3, 1/2 and −2/3
(d)1/2 ,1/6 and 2/3

Answer 1

Answer:

Total prime number : 2,3,5

Total odd number : 1,3,5

Number b/w 2 and 6 : 3,4,5

$probability = \frac{favourble \: events}{total \: event}$

For all questions answer is 1/2