13. A floor of a building consists of 2,500 tiles. All the tiles are rhombus shaped with diagonal 40 cm and 25 cm. Find the total cost of polishing the floor at the rate of ₹8 per square meter.
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Answered by
0
Answer:
1,00,000
Step-by-step explanation:
1/2*40*25 = 500
500*2500 = 1250000
1250000/100 = 12500
12500*8 = 100000 rs
Answered by
1
Answer:
Rs.1000
Step-by-step explanation:
Area of rhombus = [(Diagonal 1 x Diagonal 2)/2]. According to the formula,
Area of 1 tile=[(40x25)/2]cm²
=500cm²
No.of tiles in a floor =2500
Area of 2500 no.of tiles =(2500x500)cm²
=1250000cm²or 125m²
cost of polishing per square metre=Rs.8
so, Cost of polishing 250m² is=Rs.(125x8)
=Rs.1000. Ans
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