Question

13.
A frog in a hemispherical pod (see fig.) just floats
without sinking into sea water with density
1.35 g/cm3. If the pod has radius 6 cm and
negligible mass, what is the mass of the frog ?​

Answer 1

Answer:

Buoyant force= weight of floating object

density of liquid * volume of liquid * gravity=weight

weight = mass*gravity

1350*.4524*9.81=5991.3594=weight

5991.3594/9.8= mass

mass=610.74 N

Answer 2

The mass of the frog is 0.0152 kg.

Explanation:

Given that,

Density of sea water, $d=1.35\ g/cm^3$

Radius of the pod, r = 6 cm = 0.06 m

We need to find the mass of the frog. The density of sea water is given by the formula as follows ;

$d=\dfrac{m}{V}\\\\m=d\times V\\\\m=1.35\times \pi (0.06)^2\\\\m=0.0152\ kg$

So, the mass of the frog is 0.0152 kg.

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