Question

13. A man is four times as old as his son. After 20 years, he will be twice as old as his
son at that time. Find their present ages


please answer this question first
tomorrow is my exam​

Answer 1

Question:

_______________

13. A man is four times as old as his son. After 20 years, he will be twice as old as hisson at that time. Find their present ages

Answer:

__________

10 years, 40 years

Explanation:

_______________

Let the son's age be x years.

His father's age = 4x years

After 20 years,

Son's age = ( x + 20 ) years

Father's age = ( 4x + 20 ) years

A/q,

4x + 20 = 2( x + 20 )

4x + 20 = 2x + 40

4x - 2x = 40 - 20

2x = 20

x = 20/2

x = 10

Hence,

Son's present age = x = 10 years

Father's present age = 4x = ( 4 × 10 ) years = 40 years

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