Question

13. A point moves so that the sum of its distance from (ae,0) and (-ae,0) is 2a, prove that the locus of the point is x^2\a^2+y^2/b^2=1 where b^2=a^2(1-e^2​

Answer 1

Answer:

A point moves so that the sum of its distances from (a e ,0)a n d(-a e ,0) is 2a , prove that the equation to its locus is (x^2)/(a^2)+(y^2)/(b^2)=1 , where b^2=a^2(1-e^2)dot