Question

13. A purse contains 25-paisa and 50-paisa coins. The number of former coins is three times the
latter. If the total money in the purse is 50, find the number of coins of each type.​

Answer 1

SoluTion :-

Let the no. of 50-paisa coins be x

Then, no. of 25-paisa coins = 3x

Now,

$\sf {Value \ of \ 50 \ paisa \ coins = \dfrac{x}{2} }\\\\\\\sf {Value \ of \ 25 \ paisa \ coins = \dfrac{3x}{4}}$

According to the question,

$\sf {\dfrac{x}{2} +\dfrac{3x}{4}=50 }\\\\\\\\\sf {\dfrac{2x}{4}+\dfrac{3x}{4}=50 }\\\\\\\\\sf {\dfrac{5x}{4}=50 }\\\\\\\\\sf {x=\dfrac{50 \times 4}{5}}\\\\\\\\\sf {x=\dfrac{200}{5}}\\\\\\\\\sf {x=40}$

Thus,

No. of 50-paisa coins = x × 1 = 40

No. of 25-paisa coins = x × 1 = 120