Question

Critical temperature of H2, He, O2, N2 are 33.2K, 5.3K, 154.3K and 126K

respectively. Arrange them in the order in which they liquefy.​

Answer 1

Given:

Critical temperature of H2, He, O2, N2 are 33.2K, 5.3K, 154.3K and 126K respectively.  

To find:

Arrange them in the order in which they liquefy.​

Solution:

From given, we have,

The critical temperature of H2, He, O2, N2 are 33.2K, 5.3K, 154.3K and 126K respectively.  

02,N2,H2,He

Higher the critical temperature more easily is the gas liquefied.  

Hence, the order of liquefaction starting with the gas liquefying first will be 02, N2, H2, He.

Answer 2

Explanation:

Given Critical temperature of H2, He, O2, N2 are 33.2 K, 5.3 K, 154.3 K and 126 K respectively. Arrange them in the order in which they liquefy

• The temperature at or above which no amount of pressure will cause the gas to liquify or it cannot be liquified by pressure alone.
• As the critical temperature rises or higher the temperature the liquification of gas is very easy at room temperature.
• So the application of pressure the order of ease of liquification will be
• O2, N2, H2 and He  
• 154.3, 126, 33.2, 5.3

Reference link will be

https://brainly.in/question/16089937