Physics, asked by arpitmahajan0328, 9 months ago

13. A spherical metal shell A of radius RA and a solid
metal sphere B of radius Ro(< RA) are kept far
apart and each is given charge '+Q'. Now they
are connected by a thin metal wire. Then
(1) EN
inside
= 0
(2) QA > Qg
OA_Ro
(3)
(4) EN
on surface
A
<EM
on surface
B
OB​

Answers

Answered by inaganti25
1

Answer:

ANSWER

The potential for both the objecs is same so,

R

A

KQ

A

=

R

B

KQ

B

or

Q

B

Q

A

=

R

B

R

A

As R

B

<R

A

we get Q

A

>Q

B

Above equation represents B is correct option.

From Gauss law the electric field inside a spherical shell is zero so option A is correct.

Now σ

A

=

4πR

A

2

Q

A

and σ

B

=

4πR

B

2

Q

B

Thus

σ

B

σ

A

=

Q

B

Q

A

×(

R

A

R

B

)

2

=

R

B

R

A

×(

R

A

R

B

)

2

=

R

A

R

B

Thus option C is also correct.

Electric fields on the surface of shell and sphere are

E

A

=

ϵ

o

σ

A

and

E

B

=

ϵ

o

σ

B

Thus

E

B

E

A

=

σ

B

σ

A

<1

or

E

A

<E

B

So option D is also correct.

October 15, 2019

Similar questions