Question

One side of a rectangular field is 15 metres. The length of diagonal of this rectangular field is
17 metres. Find the area of this rectangular field.​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

AnSwer:

Let the rectangle be ABCD.

Then as per question one side of the rectangle is 15 m. So,

• Let side BC = 15m

• AC (Diagonal)= 17 m

★ By applying Pythagoras Theorem,

$\implies \sf \: \: \: {AC}^{2} = {AB}^{2} + {BC}^{2} \\ \\ \implies \sf \: \: \: AB = \sqrt{ {AC}^{2} - {BC}^{2} } \\ \\ \implies \sf \: \: \: AB = \sqrt{ {17}^{2} - {15}^{2} } \\ \\ \implies \sf \: \: \:AB = \sqrt{289 - 225} \\ \\ \implies \sf \: \: \:AB = \sqrt{64} \\ \\ \implies \sf \: \: \:{ \underline{ \boxed{ \purple{ \sf{{AB = 8 \: m }}}}}} \: \bigstar$

So now,

$\sf \implies \: Area \: of \: rectangle = l \times b \\ \\ \sf \implies \: 15 \times 8 \\ \\ \sf \implies \: { \underline{ \boxed{ \red{ \sf{120 \: {m}^{2} }}}}} \: \bigstar$

Therefore, area of the. rectangle is 120m².