Question

13. A sum of 800 is in the form of denominations of 10 and 20. If the total number of
notes is 50, find the number of notes of each type.
2​

Answer 1

Step-by-step explanation:

Let the number of 10 rupees notes be x then 20 rupees notes = (50 - x)

10x + 20(50 - x) = 800

=> 10x + 1000 - 20x = 800

=> 10x + 1000 - 800 = 20x

=> 200 = 20x - 10x = 10x

Hence, x = 200/10 = 20

10 rupees notes = x = 20

20 rupees notes = (50 - x) = 30

Answer Hence, there are 20 pieces of 10 rupees notes and 30 pieces of 20 rupees notes.

Answer 2

Answer:

The no. of notes in the form of denominations of ₹10 and ₹ 20 are 20 and 30 respectively

Step-by-step explanation:

Let the no. of notes of ₹10 be = x

Notes of ₹20 be = 50 - x

So, now

= 10x + 20 (50 - x) = 800

= 10x + 1000 - 20x = 800

= -10x = 800 - 1000 = -10x = -200

= x = 200 ÷ 10 = 20

• The no. of notes of denomination of ₹10 = 20, ₹20 = 50 - 20 = 30
• So the no. of notes in the form of denominations of ₹10 & ₹20 are 20 and 30 respectively