Math, asked by chhotelalmaurya058, 1 month ago

13. A worker was told to shape a certain gear to 7 by 9 of its

original width. If the original width of the gear was
3 by 5
cm, what should the width be after it was shaped? solve this question

Answers

Answered by pandacorn327
1

Answer:

Step-by-step explanation:

Let's try this question using only the change in volume. Since original volume = final volume, Decrease in volume = Increase in volume

You decrease volume by chopping off 9 inches of the height. Decrease = 9*w*l

You increase the volume now by adding an inch to the width and length. The height remains h-9.

Increase = 1*(l+1)*(h-9) + 1*w*(h-9) = (h-9)*(l+w+1) (make a rectangle and increase its width and length by 1 to see how area changes. This tells you how volume changes by just considering the height as well)

So 9*w*l = (h-9)*(l+w+1)

Given that (h-9) = 4w and l = w, substitute both in the equation to get

9*w*w = 4w*(2w+1)

Cancel w from both sides and get w = 4 = l

h-9 = 4w so h = 16+9 = 25

Volume = wlh = 4*4*25 = 400

_________________

Answered by sunilbhatibhati47
1

Answer:

A worker was told to shape a certain gear 7upon9 of its original width . if the original width of the gear was 3upon5cm,what should the width be after it was shaped

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