Question

13. ABCD is a trapezium with AB || DC. A line parallel to AC intersects AB at X and RC
at Y. Prove that ar (ADX) = ar (ACY).

[Hint: Join CX.]

Please no Time pass answers !!!! ​

Answer 1

Answer:

Step-by-step explanation:

Given,

ABCD is a trapezium with AB || DC & XY || AC

Construction,

Join CX .

To Prove,

ar(ADX) = ar(ACY)

Proof:

ar(△ADX) = ar(△AXC) — (i)

(On the same base AX and between the same parallels AB and CD).

also,

ar(△ AXC)=ar(△ ACY) — (ii)

 (On the same base AC and between the same parallels XY and AC.)

From (i) and (ii),

ar(△ADX)=ar(△ACY)