Question

13. An artificial satellite is moving around earth in a circular orbit with speed equal to one fourth the escape speed
of a body from the surface of earth. The height of satellite above earth's surface is (R is radius of earth)
(1) 3R
(2) 5R
(3) 7R
(4) 8R​

Answer 1

Answer:

7R

Explanation:

Orbital velocity is given as

• v = √[GM / (R + h)]

Escape velocity is given as

• v' = √(2GM / R)

It's given that

• v = v'/4

So,

√[GM / (R + h)] = (1/4) × √(2GM / R)

Squarring on both sides

[GM / (R + h)] = (1/16) × (2GM / R)

1/16 = [GM / (R + h)] × [R / (2GM)]

1/16 = R / [2(R + h)]

16R = 2(R + h)

16R = 2R + 2h

2h = 14R

h = 14R/2

h = 7R

Answer 2

Answer:

pls find the attachment

Explanation:

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