Question

13. An oblong garden 200m long and 180m wide has two cross roads in its centre. The width of
the longer road is 4m and that of the shorter road is 3m. Find the cost of watering the garden
at 30 paise per square metre.

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Answer 1

The width of street is 8.2 m.

We are given that the two buildings are parallel to each other

Refer the attached figure .

So, AB is parallel to ED

Since we are given that a ladder 5.8m long is placed on the street such that its top just reaches the window of a building at the height of 4m

So. AC = EC = 5.8 m

And AB = 4 m.

On turning the ladder over to the other side of the street its top touches the window of the other building at a height of 4.2m.

So, ED = 4.2 m

So, let BC = x and CD = y

We are required to calculate the width of street i.e. x+y

So, in ΔABC , use Pythagorean Theorem

So, in ΔEDC , use Pythagorean Theorem

So, the width of street = x+y = 4.2+4 =8.2 m

Hence the width of street is 8.2 m.

Answer 2

Answer:

the cost is 827.40

Step-by-step explanation:

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