Question

13. Calcium carbonate reacts with 50 mL of 0.2 M HCI
as per the following reaction,
CaCO3 + 2HCl(aq) →
CaCl(aq) + CO2(g) + H2O(1)
The mass of CaCO3 required to completely react with
the given HCl is
(a) 1.00 g
(b) 0.10 g
(c) 0.50 g
(d) 5.00 g
14. 0.81 g of metal carbonate react with nitrate to give
1.0 g of metal nitrate. The equivalent mass of metal
will be
(a) 53.0 (b) 106.0 (C) 212.0 (d) 80.0​

Answer 1

Answer:

1.a

2.b

Explanation:

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