Question

13. Deepak is twice as old as his brother Vikas. If the difference of their ages be 11 years, find
their present ages.
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Answer 1

Given:

Present age of

• Vikas = x
• Deepak = 2x

Difference = 11 years

What To Find:

We have to find the present age of both Vikas and Deepak.

How To Find:

To find the present age we have to

• Form an equation = 2x - x = 11
• Solve the equation.

Solution:

2x - x = 11

Subtract the terms,

⇒ x = 11

Now, substitute the values,

• Vikas' age = x = 11 years
• Deepak's age = 2x = 2 × 11 = 22 years

∴ Thus, the present age of Vikas and Deepak is 11 and 22 years respectively.

To Verify:

2x - x = 11

Substitute the values,

⇒ 2(11) - 11 = 11

Solve the brackets,

⇒ 22 - 11 = 11

Subtract 11 from 22,

⇒ 11 = 11

∴ LHS = RHS

∴ Hence, verified.