13. Determine the nature of the roots of the following quadratic equation.
i) (x-2a) (x-2b) = 4ab
ii) 9a?x? - 24abcdx + 16c+d2 = 0. a+0,b=0
iii) 2(a² +b)x² + 2 (A +b) x + 1 = 0
iv) (b + c)x? - (a + b + c)x+ a = 0
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Answer:
- Here is ur ans for (ii) here, a=9a^2b^2
- b=_24abcd
- c=16c^2d^2
- ⛰️=b^2-4ac
- (-24abcd)^2-4(9a^2b^2)(16c^2d^2)
- 576a^2b^2c^2d^2-576a^2b^2c^2d^2
- =0
- ⛰️=0
- The roots are real and unequal
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