Math, asked by shaildum21, 4 months ago

13,
Find the least number which is completely divisible by 120 and 300.
10. Find the greatest number which divides 81 and 292 leaving a remainder 3 in each case.
15. The L.C.M.of 1566 and 2030 is 54810. Find their H.C.F. and also check the answer.​

Answers

Answered by srishti1897
1

Answer:

MARK MY ANSWER AS BRAINLIEST PLEASE

Step-by-step explanation:

13. 600.

The least common multiple of 120 and 300 is 600 because 600 is the smallest number that is divisible by 120 and 300.

10.HCF of (137−2),(182−2) and (422−2).

= HCF of (135,180,420) =15.

15. LCM of 1566 & 2030= 54810

To find, HCF=?

So...We know that,

LCM ×HCF= PRODUCT of two nos.

54810x HCF =1566 x 2030

HCF= 3178980÷54810

HCF=58

HENCE ,HCF =58

Answered by nainajaincajain
1

Step-by-step explanation:

Find the greatest number which divides 81 and 292 leaving a remainder 3 in each case.

Similar questions