Question

13. Find the smallest number of 5 digits which is exactly divisible by 16, 25, 30 and
40.
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Answer 1

Answer:

10800

Step-by-step explanation:

LCM of 16,25,30 and 40 is 1200

but it is only 4 disit no.

Now 5 digit smallest no.is 10000

On dividing: 10000/1200 we get the quotient= 9

thus 1200*9=10800

hence 10800 is the smallest no.of 5 disit which is divisible by 16,25,30 and 40