13 g of benzene in 17 g CCl4 find molality
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Answer:
First: definition of molality:
molality = mol of solute per kg of solvent
Molar mass C6H6 = 78.11g/mol
13.0g C6H6 = 13.0/78.11 = 0.1664 mol
This is dissolved in 17.0g CCl4
Mol dissolved in 1kg CCl4 = 0.1664*1000/17 = 9.79 mol C6H6 dissolved in 1.0kg of CCl4
Molality = 9.79m.
Explanation:
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